the problem says to factor completely.
49w^2 -25
my answer is that it cannot be factored because there are no like terms. Is this correct thanks
algebra factoring help please?
2009-05-13 8:43 am
回答 (10)
2009-05-13 8:50 am
✔ 最佳答案
49w^2 -25=(7w+5)(7w-5) answer//
2009-05-13 8:55 am
49w² - 25 = 0
49w² = 25
w² = 25/49
w = +/- 5/7
Factors:
= w - 5/7, = 7w - 5
= w + 5/7, = 7w + 5
Answer: (7w - 5)(7w + 5) are the factors.
49w² = 25
w² = 25/49
w = +/- 5/7
Factors:
= w - 5/7, = 7w - 5
= w + 5/7, = 7w + 5
Answer: (7w - 5)(7w + 5) are the factors.
2009-05-15 10:10 am
( 7w - 5 ) ( 7w + 5 )
2009-05-13 11:25 am
a^2 - b^2 ≡ (a + b)(a - b)
49w^2 - 25
= (7w)^2 - 5^2
= (7w + 5)(7w - 5)
49w^2 - 25
= (7w)^2 - 5^2
= (7w + 5)(7w - 5)
2009-05-13 10:09 am
(7w-5)(7w+5)
2009-05-13 9:34 am
it can be factored as (7w-5)(7w+5)
2009-05-13 8:57 am
=(7w-5)(7w+5)
2009-05-13 8:55 am
49w^2 - 25
= (7w)^2 - 5^2
now I'm not sure if you know this formula:
a^2 - b^2 = (a - b)(a + b)
But, by using it ( substitute a=7w and b=5) you get:
(7w - 5)(7w + 5)
= (7w)^2 - 5^2
now I'm not sure if you know this formula:
a^2 - b^2 = (a - b)(a + b)
But, by using it ( substitute a=7w and b=5) you get:
(7w - 5)(7w + 5)
2009-05-13 8:52 am
49w^2-25 can be factorized.
49w^2=(7w)^2
25=5^2
it is in the form of a^2-b^2=(a+b)*(a-b)
ans is (7w+5)*(7w-5)
* means multiplication
49w^2=(7w)^2
25=5^2
it is in the form of a^2-b^2=(a+b)*(a-b)
ans is (7w+5)*(7w-5)
* means multiplication
2009-05-13 8:49 am
(7w-5)(7w+5)
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