Factor 9b^3 – 6b^2 please show calculations?

= 9b³ - 6b²
= 3b²(3b - 2)

Answer: 3b²(3b - 2)

16x^4 – 40x^2 + 9 to simplify calculation shall we anticipate x^2 = y , putting the value in eq. 16y^2 - 40 y + 9 16y^2 - 36y - 4y + 9 4y( 4y - 9) - a million( 4y - 9) ( 4y - 9) (4y - a million) if 4y - 9 = 0 y = 9/4 x^2 = 9/4 x = +- 3/2 and if 4y - a million = 0 y = a million/4 x^2 = a million/4 x = +- a million/2

3 b ² ( 3 b - 2 )

3b^2(3b-2)

OK look at each term. What occurs in both?

9b^3 – 6b^2

b^2 looks a good start. Divide each term by b^2

b^2*(9b-6)

Now anything else that goes into both the terms in brackets?

3 does.

so we have 3 b^2(3b-2)

so your answer is 3 b² (3b-2)

First we can take out 3b^2

Gives 3b^2 (3b - 2)

There is no further factorisation possible unless you wish to separate b^2 giving
b(3b)(3b - 2 )

9b^3 - 6b^2
= 3(3b^3 - 2b^2)
= 3b^2(3b - 2)

9b³ - 6b² = 3b²(3b - 2)

3b^2(3b - 2)