(5a^3x4a^2) divided by (15a^8)
thank u
can u please help me with this algebra question?
2009-05-10 9:55 am
回答 (9)
2009-05-10 10:06 am
✔ 最佳答案
(5a^3)(4a^2)----------------
...15a^8
...20a^5
=----------
...15a^8
......4
=---------- answer//
....3a^3
2009-05-10 5:07 pm
= (5a³[4a²])/15a⁸
= 20a⁵/15a⁸ or (20a⁵/5a⁵)/(15a⁸/5a⁵)
= 4/3a³
Answer: 4/3a³
= 20a⁵/15a⁸ or (20a⁵/5a⁵)/(15a⁸/5a⁵)
= 4/3a³
Answer: 4/3a³
2009-05-10 5:37 pm
4/5a^3
2009-05-10 5:26 pm
(5a^3 * 4a^2)/(15a^8)
= [(5 * 4)(a^3 * a^2)]/(15a^8)
= [(20)(a^5)]/(15a^8)
= (20a^5)/(15a^8)
= (20/15)(a^5/a^8)
= (4/3)(1/a^3)
= 4/(3a^3)
= [(5 * 4)(a^3 * a^2)]/(15a^8)
= [(20)(a^5)]/(15a^8)
= (20a^5)/(15a^8)
= (20/15)(a^5/a^8)
= (4/3)(1/a^3)
= 4/(3a^3)
2009-05-10 5:23 pm
Mathematics side                 Logic
(5a^3 x 4a^2) Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Multiply the terms on the top
____________ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 5 x 4 x a^(3+2) = 20 x a^5
15a^8
20a^5 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â If we had a normal fraction with 20/15 we =______ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â would simplify it to 4/3. Then using the
15a^8 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â division law we subtract the powers of "a"
                            so we get a^(5-8) = a^-3
4
=_____ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â To get a positive power we move a^-3
3a^3 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â to the denominator.
Hope this helps :)
(5a^3 x 4a^2) Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Multiply the terms on the top
____________ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 5 x 4 x a^(3+2) = 20 x a^5
15a^8
20a^5 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â If we had a normal fraction with 20/15 we =______ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â would simplify it to 4/3. Then using the
15a^8 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â division law we subtract the powers of "a"
                            so we get a^(5-8) = a^-3
4
=_____ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â To get a positive power we move a^-3
3a^3 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â to the denominator.
Hope this helps :)
參考: school work
2009-05-10 5:06 pm
If memory serves me well:-
The above reduces to 20a^5/15a^8
which again reduces to 4/3a^-3
So the answer is the cube root of 4/3a
The above reduces to 20a^5/15a^8
which again reduces to 4/3a^-3
So the answer is the cube root of 4/3a
參考: Memory
2009-05-10 5:05 pm
not so bad.....
20a^5/15a^8 = (4/3)a^(-3) or 4/(3a^3)
Just multiply and divide the numbers and powers of a.
20a^5/15a^8 = (4/3)a^(-3) or 4/(3a^3)
Just multiply and divide the numbers and powers of a.
2009-05-10 5:03 pm
(5a^3 x 4a^2) / (15a^8) = 4/(3a^3)
2009-05-10 4:58 pm
hard one huh
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