find the slope of the line 2y-5x+3=0?

The slope-intercept form of a linear equation is

y = mx + b

where "m" is the slope and "b" is the y-coordinate where the line crosses
the y-axis.

So to determine the slope from the equation 2y - 5x + 3 = 0 you'll have to solve it for y:

2y - 5x + 3 = 0

2y = 5x - 3

y = (5x - 3)/2

y = (5/2)x + (-3/2)

Now compare that to y = mx + b.

Can you see what the slope "m" is?

Add 5x to both sides:
2y+3=5x

Subtract 3 from both sides:
2y=5x-3

Divide both sides by 2:
y=(5/2)x-(3/2)

This is now in y=mx+b form where m is the slope and b is the y-intercept. The slope of this line is 5/2.

There are two ways to determine the slope of any given line. One method is to transform the given line to the standard slope-intercept form of

y = mx + b

where

m = slope
b = y-intercept

GIVEN that the equation is 2y-5x+3=0, converting it to the standard slope-intercept form,

2y = 5x - 3

and solving for "y"

y = (5/2)x - 3/2

From the above, the slope if the numerical coefficient of "x" which is 5/2.

A second method of determining the slope is to simply differentiate the given equation. Again, given that

2y-5x+3=0

Differentiating the above (y with respect to x)

2(dy/dx) - 5 = 0

and solving for dy/dx,

dy/dx = 5/2 = slope of the line

Hope this helps.

If y=ax+b,then m=a
here m=5/2

2y - 5x + 3 = 0
2y = 5x - 3
y = (5x - 3)/2
y = 5x/2 - 3/2
y = 5/2(x) - 3/2

∴ the slope is 5/2 (2.5).

Well always remember the equation y=mx+c
m being the gradient/slope.

so lets make y the subject of that equation. like so

2y = 5x - 3
y = 2.5x-1.5

m= 2.5
Slope is 2.5

Hi.
Start by writing the equation in standard form:
2y = 5x - 3
y = (5/2)x - 3/2
So the slope is 5/2 or 2,5
Hope this helped!