For 0≦x≦360, the max. and min. values of Asinx+B are 4 and -2 respectively, where A and B are real constants and A＞0.
a) Find the values of A and B.
b) Find the max. and min. values of Bsinx+A for 0≦x≦360
中四數學(英文)
2009-05-09 3:11 am
回答 (1)
2009-05-09 3:19 am
✔ 最佳答案
The question is actually simple !-2<=Asinx+B<=4
(-2-B)/A<=sinx<=(4-B)/A
=>-2-B=-A and 4-B=A
=>4-B=2+B
=>B=1,A=3
(b) 2<=sinx+3<=4
max. value=4,min. value=2
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