if g(x) = 2x + 1, find g[g(x)]
don't get it and need help. work would help me out for next time. :)
if g(x) = 2x + 1, find g[g(x)]?
2009-05-06 3:46 pm
回答 (7)
2009-05-06 3:53 pm
✔ 最佳答案
g(x) = 2x + 1,g[g(x)]=2(2x+1)+1
=4x+2+1
=4x+3 answer//
2009-05-06 11:03 pm
2(2x+1) +1
4x+3
4x+3
2009-05-06 10:58 pm
g(x) = 2x + 1
g(x) â g[g(x)]
g(x) = 2x + 1
g[g(x)] = 2(2x + 1) + 1
g[g(x)] = 4x + 2 + 1
g[g(x)] = 4x + 3
g(x) â g[g(x)]
g(x) = 2x + 1
g[g(x)] = 2(2x + 1) + 1
g[g(x)] = 4x + 2 + 1
g[g(x)] = 4x + 3
2009-05-06 10:54 pm
g(x) = 2x + 1
g[g(x)]
= g(2x + 1)
= 2(2x + 1) + 1
= 4x + 2 + 1
= 4x + 3
g[g(x)]
= g(2x + 1)
= 2(2x + 1) + 1
= 4x + 2 + 1
= 4x + 3
2009-05-06 10:53 pm
g(x) = 2x + 1
g[g(x)] = g (2x+1)
= 2 (2x+1) +1
= 4x +2 +1
= 4x +3
g[g(x)] = g (2x+1)
= 2 (2x+1) +1
= 4x +2 +1
= 4x +3
2009-05-06 10:52 pm
g[g(x)] = 2(2x + 1) + 1
g[g(x)] = 4x + 2 + 1
g[g(x)] = 4x + 3
g[g(x)] = 4x + 2 + 1
g[g(x)] = 4x + 3
2009-05-06 10:50 pm
(g o g)(x) = 4x + 3
收錄日期: 2021-05-01 12:20:20
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090506074657AAnL6Hy