高中數學難題AR..>
回答 (2)
2009-05-04 12:55 pm
✔ 最佳答案
底半徑 = √(S/π)高 = Q/√(S/π)
圓錐的體積 = 1/3*S*Q/√(S/π) = Q√(Sπ) / 3
2009-05-04 5:21 pm
Let base radius of cone = r, height of cone = h.
pr^2 = S ( p = pi)............(1)
h(2r)/2 = hr = Q...............(2)
From (1) = r = sqrt(S/p), sub. into (2) we get
h = Q/r = Q/sqrt(S/p).
so Volume of cone = pr^2h/3 = S[Q/sqrt(S/p)]/3.
2009-05-04 09:23:01 補充：
Answer can be simplified to [Q sqrt(pS)]/3
pr^2 = S ( p = pi)............(1)
h(2r)/2 = hr = Q...............(2)
From (1) = r = sqrt(S/p), sub. into (2) we get
h = Q/r = Q/sqrt(S/p).
so Volume of cone = pr^2h/3 = S[Q/sqrt(S/p)]/3.
2009-05-04 09:23:01 補充：
Answer can be simplified to [Q sqrt(pS)]/3
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