Solve for a: [9(r^2) +9(a^2)]=35?
回答 (5)
2009-05-03 4:28 pm
✔ 最佳答案
9r^2 + 9a^2 = 35r^2 + a^2 = 35/9
a^2 = (35/9) - r^2
a = +/- sqrt((35/9) - r^2)
hope this helps! :)
2009-05-03 11:50 pm
9r^2 + 9a^2 = 35
9a^2 = -9r^2 + 35
a^2 = (-9r^2 + 35)/9
a = 屉[(-9r^2 + 35)/9]
a = [屉(-9r^2 + 35)]/3
9a^2 = -9r^2 + 35
a^2 = (-9r^2 + 35)/9
a = 屉[(-9r^2 + 35)/9]
a = [屉(-9r^2 + 35)]/3
2009-05-03 11:35 pm
9a^2=35-9r^2
a=+ & -(35-9r^2)/9^1/2=+ & - [(35-9r^2)^1/2]/3
a=+ & -(35-9r^2)/9^1/2=+ & - [(35-9r^2)^1/2]/3
2009-05-03 11:33 pm
[9(r^2) +9(a^2)]=35 (Divide the whole equation by 9) So:
r^2 + a^2 = 35/9 (Then send the r^2 to the other side)
a^2 = 35/9 - r^2 (then use the square root property to get "a" by itself)
a= +/- Square Root of ((35/9) - r^2)
r^2 + a^2 = 35/9 (Then send the r^2 to the other side)
a^2 = 35/9 - r^2 (then use the square root property to get "a" by itself)
a= +/- Square Root of ((35/9) - r^2)
2009-05-03 11:30 pm
robin is right
收錄日期: 2021-05-01 12:20:37
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