How do i solve for "a" in(a-5b)/(a+5b)=(-7k-5)?
回答 (3)
2009-05-03 4:38 pm
✔ 最佳答案
a-5b---------=-7k-5
a+5b
a-5b=(-7k-5)(a+5b)
a-5b=-7ak-35bk-5a-25b
5b+35bk+25b=-7ak-5a-a
20b+35bk=-7ak-6a
20b+35bk=a(-7k-6)
.....20b+35bk
a=--------------------
.......-7k-6
....5b(7k+4)
a=------------------ answer//
.....-(7k+6)
2009-05-03 11:22 pm
-(7k + 5) * (a + 5b) = a - 5b
-a * (7k + 5) - 5b(7k + 5) + 5b = a
5b - 5b(7k + 5) = a + a * (7k + 5)
5b( 1 - 7k - 5) = a ( 1 + 7k + 5)
-5b * (4 + 7k) / (6 + 7k) = a
-a * (7k + 5) - 5b(7k + 5) + 5b = a
5b - 5b(7k + 5) = a + a * (7k + 5)
5b( 1 - 7k - 5) = a ( 1 + 7k + 5)
-5b * (4 + 7k) / (6 + 7k) = a
2009-05-03 11:21 pm
(a - 5b)/(a + 5b) = -7k - 5
a - 5b = (-7k - 5)(a + 5b)
a - 5b = -7ka - 5a - 35kb - 25b
a + 7ka + 5a = 5b - 35kb - 25b
a(1 + 7k + 5) = [5b(1 - 7k - 5)]
a = [5b(-7k - 4)]/(7k + 6)
a - 5b = (-7k - 5)(a + 5b)
a - 5b = -7ka - 5a - 35kb - 25b
a + 7ka + 5a = 5b - 35kb - 25b
a(1 + 7k + 5) = [5b(1 - 7k - 5)]
a = [5b(-7k - 4)]/(7k + 6)
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