解下列方程
2 tan^2x + 5 tan x - 3 = 0
2 cos ^2x - cos x = 0
#Reminder: Please list out all the steps you calculated.
Maths (10 marks)
2009-05-02 11:57 pm
回答 (2)
2009-05-03 1:35 am
✔ 最佳答案
2 tan2x + 5 tan x - 3 = 0(2tanx-1)(tanx+3)=0
tanx=1/2 or tanx=-3
x= 26.6o,108.4o,206.6o,288.4o
2 cos 2x - cos x = 0
cosx(2cosx-1)=0
cosx=0 or cosx=1/2
x=60o,90o,270o,300o
2009-05-03 12:03 am
(tanx+3)(2 tan x - 30=0
tanx=-3 OR tanx=0.5
x=288,108,23.6,333
2 cos ^2x - cos x = 0
2 cos ^2x - cos x = 0
cos x(2cos x-1)=0
cos x=0 OR cos x=1/2
x=90,270,60, 300
tanx=-3 OR tanx=0.5
x=288,108,23.6,333
2 cos ^2x - cos x = 0
2 cos ^2x - cos x = 0
cos x(2cos x-1)=0
cos x=0 OR cos x=1/2
x=90,270,60, 300
收錄日期: 2021-04-23 20:37:19
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090502000051KK01086