✔ 最佳答案
The most common method is to take moment about the new centre of mass
In your example, let
L be the length of string
mg be the weight of the string
Mg be the weight of the suspended object
The centre of mass of the string is at the middle of the length of the string, i.e. L/2 from each end.
In that case, it is expected that the new centre of mass of the string and the object combined together is somewhere between the centre of mass of the string at L/2 and the lower end of the string.
Let the position of the new centre of mass be x from the lower end of the string. Hence, taking moment about this new centre of mass,
Mg.(x) = mg.(L/2-x)
thus, Mx = mL/2 - mx
i.e. x = mL/2(M+m)
Therefore, the new centre of mass is at a distance of mL/2(M+m) from the lower end of the string.