Solve
(w-3)(w+1)=0
(If there is more than one solution, separate them with commas.)
w=
MATH help PLEASE!!!!!!?
2009-05-02 4:19 am
回答 (7)
2009-05-02 4:24 am
✔ 最佳答案
You almost solved it on your own. Just set each factor equal to zero and solve for w:w-3=0
w=3
w+1=0
w=-1
And so if you wanted the solutions separated by a comma:
w = 3, -1
Have a good day!
2009-05-02 1:42 pm
(w - 3)(w + 1) = 0
w - 3 = 0
w = 3
w + 1 = 0
w = -1
â´ w = -1 , 3
w - 3 = 0
w = 3
w + 1 = 0
w = -1
â´ w = -1 , 3
2009-05-02 11:28 am
(w-3)(w+1)=0
(w-3)
w=3
(w+1)
w=-1
substitute 3
(w-3)(w+1)
(3-3)(3+1)
(0)x(4)=0
substitute -1
(w-3)(w+1)
(-1-3)(-1+1)=0
(-4)x(0)=0
so the answers are:
w=3
w=-1
(w-3)
w=3
(w+1)
w=-1
substitute 3
(w-3)(w+1)
(3-3)(3+1)
(0)x(4)=0
substitute -1
(w-3)(w+1)
(-1-3)(-1+1)=0
(-4)x(0)=0
so the answers are:
w=3
w=-1
參考: me!!
2009-05-02 11:25 am
Set each factor equal to zero because at least one must equal zero. THere are two solutions. w-3=0 w+1=0
w=3 w=-1
w=3 w=-1
2009-05-02 11:25 am
w=3,w=-1
2009-05-02 11:25 am
foiled= w^2-2w-3
Zeros: W=3 W= -1
Zeros: W=3 W= -1
收錄日期: 2021-05-01 12:20:05
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