2 questions of Absolute value

1 when x<-7/2
〡 2x+7〡-〡 x-3〡= 16
-7-2x-3+x= 16
-x=26
x=-26
when -7/2<x<3
〡 2x+7〡-〡 x-3〡= 16
2x+7-3+x= 16
3x=12
x=4 (rejected)
when x>3
〡 2x+7〡-〡 x-3〡= 16
2x+7-x-3= 16
x=6
So x=-26 or 6

2when x<2
〡x-2〡( x -3 ) = 2
(2-x)(x-3)=2
x^2-5x+8=0
no solution
when x>2
〡x-2〡( x -3 ) = 2
(x-2)(x-3)=2
x^2-5x+4=0
x=4 or 1 (rejected)