Find the point of intersection of each of the following pairs of lines.
1. Ｌ1 : 3x+6=0 and Ｌ2 : 2y-4=0
2. Ｌ1 : x=4 and Ｌ2 : 2x+3y=2
please詳細解答, thanks a lot
中四數學(20點)
2009-05-02 6:10 am
回答 (2)
2009-05-02 6:39 am
✔ 最佳答案
找兩綫交點，需要使用聯立方程將兩式聯立
3x+6=0 ..........(i)
2y-4=0............(ii)
from(i), 3x=-6
x=-2
from(ii) 2y=4
y=2
所以交點係(-2,2)
x=4 ..........(i)
2x+3y=2...........(ii)
將(i)代入(ii)
2(4)+3y=2
y=-2
所以交點係(4,-2)
參考: King
2009-05-02 6:41 am
Q1.
3x + 6 = 0 that is x = -6/3 = -2 which is a vertical line .
2y - 4 = 0 that is y = 4/2 = 2 which is a horizontal line.
so the point of intersection is x = - 2 and y = 2 or (-2,2).
Q2.
Sub. x = 4 into L2 we get 2(4) + 3y = 2, so 3y = 2 - 8 = - 6
y = -6/3 = - 2. The point of intersection is therefore ( 4, -2).
3x + 6 = 0 that is x = -6/3 = -2 which is a vertical line .
2y - 4 = 0 that is y = 4/2 = 2 which is a horizontal line.
so the point of intersection is x = - 2 and y = 2 or (-2,2).
Q2.
Sub. x = 4 into L2 we get 2(4) + 3y = 2, so 3y = 2 - 8 = - 6
y = -6/3 = - 2. The point of intersection is therefore ( 4, -2).
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