有一條化學計算請教?

某溶液在2.0cm的吸收池測量時,T=60%,若在1.0cm或3.0cm的吸收池測定時透光率各為 多少?

T = 透光率
ε = 摩爾吸光系數 (L mol-1 cm-1)
b = 路徑長度 (cm)
c = 溶液濃度 (mol L-1)

應用公式： -log10T = εbc

ε 和 c 保持不變。

當 b = 2.0 cm，T = 60%：
- log1060% = ε(2.0)c
εc = (-log1060%)/2 ...... (1)

當 b = 1.0 cm：
-log10T = εbc = εc(1.0) = [(-log1060%)/2] x (1.0)
log10T = (log1060%)/2 = -0.1109
透光率 T = 10-0.1109 = 77.5%

當 b = 3.0 cm：
-log10T = εbc = εc(3.0) = [(-log1060%)/2] x (3.0)
log10T = 3(log1060%)/2 = -0.3328
透光率 T = 10-0.3328 = 46.5%

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1um=?cm=?微米=?m

微米的符號是 μm，1μm 等於 1 x 10-6 m。而 1 cm 等於 1 x 10-2 m。所以：

1 μm = 1 x 10-4 cm = 1 微米 = 1 x 10-6 m
=