solve the quadratic formula...stuck?

2009-04-30 6:47 am
4x^2 + 12x + 6 = 0

回答 (4)

2009-04-30 6:52 am
✔ 最佳答案
Why don't you look at my answer to the first question that you asked, then apply it to this one. See if you can't figure it out from there.
2009-04-30 1:56 pm
4x² + 12x + 6 = 0
x² + 3x = - 3/2
x² + 3/2x = - 3/2 + (3/2)²
x² + 3/2x = - 6/4 + 9/4
(x + 3/2)² = 3/4
x + 3/2 = 0.8660255

x = 0.8660255 - 1.5, x = - 0.6339745
x = - 0.8660255 - 1.5, x = - 2.3660255

Answer: x = - 0.6339745, - 2.3660255; Factors: 4(x + 0.6339745)(x + 0.23660255)
2009-04-30 5:34 pm
4x^2 + 12x + 6 = 0
2x^2 + 6x + 3 = 0
x = [-b ±√(b^2 - 4ac)]/2a

a = 2
b = 6
c = 3

x = [-6 ±√(36 - 24)]/4
x = [-6 ±√12]/4
x = [-6 ±√(2^2 * 3)]/4
x = [-6 ±2√3]/4
x = [-3 ±√3]/2

∴ x = [-3 ±√3]/2
2009-04-30 2:47 pm
Use the quadratic formula to find the answer.


收錄日期: 2021-05-01 12:19:54
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090429224742AAcsKle

檢視 Wayback Machine 備份