Which expression is a factor of 4x^2+2x-2?

4x^2 + 2x - 2
= 2(2x^2 + x - 1)
= 2(2x^2 + 2x - x - 1)
= 2[(2x^2 + 2x) - (x + 1)]
= 2[2x(x + 1) - 1(x + 1)]
= 2(x + 1)(2x - 1)
(answer B)

4x² - 4x - 3 = 0 the classic recommendations-set of (4x )(x ) won't paintings by using making use of actuality the middle term could be off no count quantity how we place the 'one million' and the '3' and the '+'s and '-'s. So, the acceptable we are waiting to do is to pull out 4x 4x(x - one million) - 3 = 0

2 (2 x ² + x - 1)

2 ( 2x - 1 ) ( x + 1)

OPTION B

B

4x² + 2x - 2
= 2(2x² + x - 1)
= 2(2x - 1)(x + 1)

So the answer is B

Use the quadratic formula and you will find that the answer is B

-b ± sqrt(b² - 4ac)
----------------------------
2a

(X+1)

forsure

Factor the whole expression. One first guess would get you:
(4x + ?) (x - ?) or (4x - ?) (x + ?)
Now, what are the factors for the last term (2)? Ans. 1 and 2
Now, which one coudl go where to get +2x in the middle spot?
Try:
(4x + 1)(x - 2) - Does that work?
4x^2 + x - 8x - 2 ....... No
So try the other possible form:
(4x - 1) (x + 2) - Does that work?
4x^2 - x + 8x - 2 ........ No
So, reverse the order of the factors of 2 and see if that works:
(4x + 2) (x - 1) - Does that work?
4x^2 + 2x - 4x - 2 ...... No
Last possibility:
(4x - 2) (x + 1) - Does that work?
4x^2 - 2x + 4x - 2 ..... Yes
Now, look at the possible answers and, indeed, the "B" selection seems to be the one.

study ur books

B

=2(x^2+x-1)
=2(x+1)(2x+1)