Multiplying radical expressions?

2009-04-29 8:21 am
I cant figure out how to multiply this expression and am totally stuck. Please help!

(2√21)(3√6)

回答 (6)

2009-04-29 8:27 am
✔ 最佳答案
= 2 * 3 * √21 * √6
= 6 * √(21*6)
= 6 * √(3 * 7 * 2 * 3)
= 6 * 3√14
= 18√14
2016-10-18 10:57 pm
to multiply radicals, use distributive property as with numbers as quickly as you get an mind-blowing variety of the comparable numbers indoors an in depth take 0.5 of them out and multiply each and every and each of them via the coefficient. additionally, in basic terms upload radicals in the event that they have comparable extensive form indoors radical 4a) sqrt(2)*[3*sqrt(10) + 2*sqrt(2)] 3*sqrt(10*2) + 2*sqrt(2*2) 12*sqrt(5) + 8*sqrt 4b) [sqrt(2) + sqrt(7)]*[sqrt(3) - sqrt(7)] first outer inner very final so sqrt(2) tiimes sqrt(3) sqrt(2) situations sqrt(7) sqrt(7) situations sqrt(3) sqrt(7) situations sqrt(7) sqrt(2) tiimes sqrt(3) equals to sqrt(6) sqrt(2) situations sqrt(7) equals to sqrt(14) sqrt(7) situations sqrt(3) equals to sqrt(21) sqrt(7) situations sqrt(7) equals to 7 upload them at a similar time: sqrt(6) + sqrt(14) + sqrt(21) + 7
2009-04-29 9:56 am
6 √21 √6 = 6 √3 √7 √2 √3 = 18 √14
2009-04-29 9:55 am
(2√21)(3√6)
= (2 * 3)√(21 * 6)
= 6√126
= 6√(3^2 * 14)
= 6(3)√14
= 18√14
2009-04-29 8:35 am
(2√21)(3√6) = (2)*(3)*√(21*6)
= (6)*√(7*3*3*2) = (6)*(3)√(14)
= 18√14 ................ answer
2009-04-29 8:34 am
6 * √21 * √6 = 6 √126 = 18√14


收錄日期: 2021-05-01 12:19:21
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090429002149AAPGxwX

檢視 Wayback Machine 備份