代數式的簡化

1. 最小公倍數 L.C.M (lowest common multiple)

L.C.M. of 6 and 4 係 12

(3x+1)/6 - (2x+3)/4
=(6x+2)/12 - (6x+9)/12
=(6x + 2 - 6x - 9)/12
=7/12

2. L.C.M. of 8 and 4 係8

(4x-3)/8 - (3x+1)/4
=(4x-3)/8 - (6x+2)/8
=(4x - 3 - 6x - 2)/8
= (-2x - 5)/8

3x+1)/6－(2x+3)/4=????
Sol
[6,4]=12
A=(3x+1)/6-(2x+3)/4
12A=12*[(3x+1)/6-(2x+3)/4]
=2*(3x+1)－3*(2x+3)
=6x+2-6x－9
=－7
A=－7/12
(3x+1)/6-(2x+3)/4=－7/12
Q.2
不知