how do you solve the problem √x+1=4?

√x+1=4
x+1=16(squaring on both sides)
x=15

√(x + 1) = 4
x + 1 = 16
x = 15

Answer: x = 15

Checking:
√(15 + 1) = 4
√16 = 4
4 = 4

x=9 if the x+1 is not in brackets
x=15 if the x+1 is in brackets

√(x + 1) = 4
x + 1 = 4^2
x + 1 = 16
x = 16 - 1
x = 15

you're able to do it with algebra, or with a calcultor, or by skill of adjusting to decimals. yet this question is extremely uncomplicated that it in basic terms takes extremely good judgment. If x + a million/4 = a million/2, then a million/2 - a million/4 = x. in case you do no longer 'get' that genuine away , think of roughly it. in case you had some substitute on your pocket and that i gave you 1 / 4, after which you had 50 cents, how plenty money did you have till now? You had the 50 cents you have now minus the quarter I gave you, this is 25 cents. it extremely is in basic terms logical. ok, so a million/2 = 2/4, so take a million/4 far off from 2/4, and you get a million/4. a million/4 + a million/4 = a million/2. So x replaced right into a million/4. Or 2/8, comparable ingredient.

sq rt of x+1=4
square both sides

x+1=16
x=15

question is not quite clear you know
I will give you two answers then

(√x+1) = 4
x + 1 = 16
x= 15

√x + 1= 4
√x = 3
x= 9

That's it Maths rock

Will you more careful to write rt(x+1) or (rtx)+1 from next time?
See got different answers!

x+1=4^2
x=4^2-1
x=15

First you move the one to the other side next to four and it becomes -1. 4-1=3. X squared is 3 so x =6