maths question!! help?
how would i solve:
3(2-3y/2)
do i multiply everything in the brackets by 3, or do just multiply everything on the top (numerator) by 3. im confused..
回答 (8)
✔ 最佳答案
3(2-3y/2)
6-9y/2 answer//
take LCM for 2 and 3y/2
3/2(4-3y)= 0
4-3y=0
3y=4
answer y=4/3
actually this is already good you know, but yeah you can multiply 3 inside a bracket 6-9y / 2
3(2 - 3y/2)
= 3*2 - 3*3y/2
= 6 - 9y/2
Just expand it and rearrange with the highest power first. Divide by 2.
3(2-3y/2)
=6-9y/2
=-9y/2+6
=-18y+12
you would multiply the numerator by 3.
if you multiplied the numerator and denominator by 3 you could just take a 3 out of the top and bottom and cancel it, and it wouldn't make a difference.
Solve inside the bracket
2-(3y/2)
take the lcm and you get the answer
(4-3y)/2
Multiply the result by 3
3((4-3y)/2)
your answer is
(12-9y)/2
if you dont want to do this way then it will be, multiply 3 by each of the numbers
your answer will be
6 - 9y/2
收錄日期: 2021-05-01 12:21:01
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