1.Factorize 3a-2ab+6a^2-b
2.Determine whether the point (8,-3) is on the straight line 3x+4y-12=0
3.Change the subject of the formula A= (a+b)h/2 to b.
F.2 Math急急!!!!!!!
2009-04-27 5:18 am
回答 (1)
2009-04-27 6:10 am
✔ 最佳答案
1)3a-2ab+6a^2-b
=3a+6a^2-2ab-b
=3a(1+2a)-b(1+2a)
=(1+2a)(3a-b)
2)
Since 3(8)+4(-3)-12=0
Hence the point (8,-3) is on the straight line 3x+4y-12=0
3)
A= (a+b)h/2
2A=(a+b)h
2A/h=a+b
b=(2A/h)-a
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