Suppose the graph of y= x^2 - 2x - 3 is given. in order to solve the quadratic equation 2x^2 - 6x - 3 = 0 , which of the following straight lines should be added to the given graph?
A. y = 4x
B. y = x - 3/2
C. y = -x + 3/2
D. y = 2x - 3
E. y = - 2x + 3
add a line to slove quadratic
2009-04-27 1:48 am
回答 (2)
2009-04-27 2:09 am
✔ 最佳答案
B. y = x - 3/2Since y= x^2 - 2x - 3.
when y = x - 3/2,
x - 3/2= x^2 - 2x - 3
x^2 - 2x - 3 - x + 3/2 = 0
x^2 -3x - 3/2 = 0
2x^2 - 6x -3 = 0
2009-04-27 3:23 am
B?!
2009-04-26 19:23:05 補充：
2x2 - 6x - 3=
x2-3x -3/2=0
x2-3x=3/2
x2-2x=x+3/2
x2-2x-3=x- 3/2
It should be added y = x - 3/2
2009-04-26 19:23:05 補充：
2x2 - 6x - 3=
x2-3x -3/2=0
x2-3x=3/2
x2-2x=x+3/2
x2-2x-3=x- 3/2
It should be added y = x - 3/2
收錄日期: 2021-04-23 20:45:23
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090426000051KK01420