how do i solve 3x 4 = 1/4 x?

2009-04-25 1:07 pm
equations with fractions

回答 (10)

2009-04-25 1:15 pm
✔ 最佳答案
ur question seems to be difficult to understand....
is it 3x^4 ?????
i think so....
if it is that then
3x^4 = x/4
3x^3 = 1/4
x^3 = 1/12
x = (1/12)^(1/3)
answer

or if it is 3*4 = 12 then
12 = 1/4 x
= > x = 48 answer
2009-04-28 10:50 pm
3x+4=1/4x

3x+4(4)=1/4x(4)
4(3x+4)=x
12x+16=x
2009-04-25 9:08 pm
(3x)(4) = 1/4(x)
12x = x/4
12x - x/4 = 0
x(12 - 1/4) = 0
x = 0
2009-04-25 8:40 pm
3*4 = x/4

12 = x/4

x= 48
2009-04-25 8:30 pm
oh I used to get stuck on these all the time!

okay first u need to multiply 3 x 4.

3 x 4 = 1/4 x
12 = 1/4 x

then u need to get x alone.. so u divide 1/4 from either side

12 = 1/4 x
12 divided by 1/4 = .25
1/4 divided by 1/4. you cross cancel so it equals 0.

then I think u multiply

12 x .25 = x
48 = x
參考: 1 semester math
2009-04-25 8:24 pm
If you had a quarter of anything you would know that something had been cut into 4 pieces

To make x into a whole you will have to multiply by 4
to give 1/4 times 4 makes 1x

You can do this with an equation as long as you multiply everything in the equation by 4 to keep a balance (like weighing scales)

So your sum 12 = 1/4x will become 48 = x
So x = 48
2009-04-25 8:17 pm
48x^2=1
x^2=1/48
x= + & - 0.14433
2009-04-25 8:16 pm
Well
3 X 4= 12 right, but the answer is a quarter times X so you multiply 12 by 4 which equals 48

so 3 X 4 = 1/4 X 48
2009-04-25 8:15 pm
3x4 = 1/4x
12 = 1/4x
cross multiply,
x=48
2009-04-25 8:26 pm
there is a bit of ambiguity in your question
im not too sure what 3x 4 is
perhaps you omitted a /
1/4 x is also ambiguous, as it can imply 1/(4x) or (1/4)x

but if the equation was 3x / 4 = (1/4)x
-cross multiply
=> 3x / 4 = x / 4
=> 3x*4 = 4x
=> 12x = 4x
=> 8x = 0
x = 0

or if the equation was (3x)4 = (1/4)x
=> 12x = x / 4
=> 48x = x
=> 47x = 0
x = 0

or if the equation was (3x)4 = 1/(4x)
=> 12x = 1(4x)
=> 48x^2 = 1
x = 1 / 48
x = + or - 1/ [sqrt(48)]
x = + or - 1 / [4sqrt (3)]

or if the equation was 3x / 4 = 1/(4x)
=> 12x^2 = 4
=> x^2 = 1 / 3
=> x = + or - 1/sqrt(3)

sorry i cant really help much because your equation is a bit ambiguous


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