What is the sum of 3a-b, 2a +c, 2b – 4d and 3b-a +2d-2c?

3a - b + 2a + c + 2b - 4d + 3b - a + 2d - 2c
= 3a + 2a - a - b + 2b + 3b + c - 2c - 4d + 2d
= 4a + 4b - c - 2d

So the answer is 4a + 4b - c - 2d

4a+4b-c-2d

Q.3a-b + 2a +c + 2b – 4d + 3b-a +2d-2c

Ans. 3a - b
+ 2a + c
+ + 2b - 4d
+ -a+ 3b - 2c+ 2d
__________________
4a +4b - c - 2d(ans)

3a_____ - b
2a_____________c
________2b_____________- 4d
- a______3b____- 2c______ 2d

4a + 4b - c - 2d

3a -b
2a +c
2b -4d
-a +3b -2c +2d
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4a+4b-c-2d
good luck.

the answer will remain the same coz they are of different coefficients.. you should have the same in order for you to add or subtract it. For example.. 3a-a is equal to 2a.. as opposed to 3a-b is still equal to 3a-b. Hope this helps. :)

(3a - b) + (2a + c) + (2b - 4d) + (3b - a) + (2d - 2c)
= 3a - b + 2a + c + 2b - 4d + 3b - a + 2d - 2c
= 3a + 2a - a - b + 2b + 3b + c - 2c - 4d + 2d
= 4a + 4b - c - 2d

5a plus 4b plus c minus 2d

all as one sum or are thay all seperate?

what is the value of A , B , C , and D?