✔ 最佳答案
Let n be the basicity of citric acid,
and denote citric acid as HnX.
HnX + nNaOH → NanX + nH2O
Mole ratio HnX : NaOH = 1 : n
Molarity of HnX = 9.06/192 = 0.0472 M
No. of moles of HnX used = 0.0472 x (25/1000) = 0.00118 mol
No. of moles of NaOH = 0.42 x 7.5/1000 = 0.00315
Basicity, n = 0.00315/0.00118 ≈ 3
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