help with algebra problem?

x = 3, y = -4
2x - 3y^2 =>

2*3 - 3*(-4)^2 =
= 6 - 3*16 =
= 6 - 48 =
= -42

36 if the ^ symbol is multiplication, or 9 if the ^ symbol means division

What is to be done? evaluate? Just substitute the values.
If x = 3, how much is 2x?
If y = 2 how much is y^2? and 3y^2?
Can you do it now?

6 - -12^2

6 - 144

-138

2x - 3y^2 (x = 3,y = -4)
= 2(3) - 3(-4)^2
= 6 - 3(16)
= 6 - 48
= -42

Substitute the x and y values.

2(3)-3(-4)^2= 6-48 = -42 <--answer

2 (3) -3 (-4) ^ 2
6 - 12 ^ 2
6 - 144

I think it is right but don't bet on it.

so 2x3=6
=6-3y^2
3y^2=48
=-42 i think
i hope this helps

substitute the given value for x and y in the formula...

2x-3y^2

2(3) - 3(-4)^2

2(3) - 3(16)

6-48

-42

wow just plug in the numbers. 6-48