x = 3, y = -4
2x - 3y^2
help with algebra problem?
2009-04-23 10:46 am
回答 (10)
2009-04-23 10:57 am
✔ 最佳答案
x = 3, y = -42x - 3y^2 =>
2*3 - 3*(-4)^2 =
= 6 - 3*16 =
= 6 - 48 =
= -42
2009-04-23 10:53 am
36 if the ^ symbol is multiplication, or 9 if the ^ symbol means division
2009-04-23 10:52 am
What is to be done? evaluate? Just substitute the values.
If x = 3, how much is 2x?
If y = 2 how much is y^2? and 3y^2?
Can you do it now?
If x = 3, how much is 2x?
If y = 2 how much is y^2? and 3y^2?
Can you do it now?
2009-04-23 10:51 am
6 - -12^2
6 - 144
-138
6 - 144
-138
2009-04-23 11:31 am
2x - 3y^2 (x = 3,y = -4)
= 2(3) - 3(-4)^2
= 6 - 3(16)
= 6 - 48
= -42
= 2(3) - 3(-4)^2
= 6 - 3(16)
= 6 - 48
= -42
2009-04-23 11:04 am
Substitute the x and y values.
2(3)-3(-4)^2= 6-48 = -42 <--answer
2(3)-3(-4)^2= 6-48 = -42 <--answer
2009-04-23 10:58 am
2 (3) -3 (-4) ^ 2
6 - 12 ^ 2
6 - 144
6 - 12 ^ 2
6 - 144
2009-04-23 10:56 am
I think it is right but don't bet on it.
so 2x3=6
=6-3y^2
3y^2=48
=-42 i think
i hope this helps
so 2x3=6
=6-3y^2
3y^2=48
=-42 i think
i hope this helps
2009-04-23 10:51 am
substitute the given value for x and y in the formula...
2x-3y^2
2(3) - 3(-4)^2
2(3) - 3(16)
6-48
-42
2x-3y^2
2(3) - 3(-4)^2
2(3) - 3(16)
6-48
-42
2009-04-23 10:51 am
wow just plug in the numbers. 6-48
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