Maths Problems!!!!!!!!!!!

2009-04-23 10:44 am
how do you solve inequations and percentages and more

3x + 7 > 13

7y - 5 < 23

4p - 4 < 2p + 20

58 - y > 7y + 2

a x 3 x c

2p x 3q

4t x 2r x 5s

m x 3m

k x k x k

j x j - 3

17.5% of $240 and 72 , 760

1 1
1 + 3
2 4

回答 (2)

2009-04-23 7:25 pm
✔ 最佳答案
3x+7&amp;gt;13
3x&amp;gt;13-7
3x&amp;gt;6
x&amp;gt;2

7y-5&amp;lt;23
7y&amp;lt;23+5
7y&amp;lt;28
y&amp;lt;4

4p - 4&amp;lt;2p + 20
4p-2p&amp;lt;20+4
2p&amp;lt;24
p&amp;lt;12

58 - y&amp;gt;7y + 2
58-2&amp;gt;7y+y
56&amp;gt;8y
7&amp;gt;y
y&amp;lt;7

a x 3 x c
=3ac

2p x 3q
=6pq

4t x 2r x5s
=40rst

m x 3m
=3m&amp;sup2;

k x k x k
=k&amp;sup3;

j x j - 3
=j&amp;sup2;-3

17.5% of $240
=$240(17.5%)
=$42

17.5% of $72 , 760
=$72760(17.5%)
=$12733

2009-04-23 11:26:11 補充:
參考資料:http://hk.knowledge.yahoo.com/question/question?qid=7009042300177
2009-04-24 4:04 am
3x + 7 > 13
3x > 13-7
3x > 6
x > 2

7y - 5 < 23
7y < 23+5
7y < 28
y < 4

4p - 4 < 2p + 20
4p + 2p < 20 + 4
6p < 24
p < 4

58 - y > 7y + 2
58 - 2 > 7y + y
56 > 8y
7 > y
y < 7

a x 3 x c
= 3ac

2p x 3q
= (2)(p)(3)(q)
= 6pq

4t x 2r x 5s
= (4)(t)(2)(r)(5)(s)
= 40trs

m x 3m
= 3m^2

k x k x k
= k^3

j x j - 3
= j^2 - 3

17.5% of $240
= 240 x 17.5%
= 42

17.5% of 72
= 72 x 17.5%
= 12.6

17.5% of 760
= 760 x 17.5%
= 133

什麼是↓
1 1
1 + 3
2 4


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