Use the rules of logarithms to write 2log63 + 5log62 - 3log62 as a single number?
回答 (3)
2009-04-22 9:51 am
✔ 最佳答案
2log63 + 5log62 - 3log62= 2log63 + 2log62
= 2(log63 + log62)
= 2log(63 * 62)
= 2log3906
2009-04-22 3:42 pm
Is it by chance :-
2 log 62 + 5 log 62 - 3 log 62 ?
4 log 62
7.17
2 log 62 + 5 log 62 - 3 log 62 ?
4 log 62
7.17
2009-04-22 3:30 pm
2log63 + 5log62 - 3log62 = log63^2 + 2log62 = log 63^2 + log62^2 = log(62^2*63^2) = log 3906^2 = log 15,256,836
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