1. cosθsinθtanθ-1
2. 2sinθ-3cosθ/4cosθ
3. if sinA=2/3, cosA/tanA+sinA=?
F.2 math 急
2009-04-20 12:20 am
回答 (2)
2009-04-20 2:19 am
2009-04-20 12:33 am
1.tanθ=sinθ/cosθ
cosθx sinθx sinθ/cosθ-1
sin^2θ-1=cos^2θ
2009-04-19 16:48:19 補充：
A~=41.8 USE YOUR CALCULATOR
SUB THE A(41.81031489)INTO THE FORMULA
YOU CAN HAVE THE ANS 1.5
cosθx sinθx sinθ/cosθ-1
sin^2θ-1=cos^2θ
2009-04-19 16:48:19 補充：
A~=41.8 USE YOUR CALCULATOR
SUB THE A(41.81031489)INTO THE FORMULA
YOU CAN HAVE THE ANS 1.5
收錄日期: 2021-04-23 20:38:03
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090419000051KK01281