How do you simplify 3(2x + 1) + 2 (x-4)?
How do you simplify 3(2x + 1) + 2 (x - 4)?
回答 (14)
= 3(2x + 1) + 2(x - 4)
= 6x + 3 + 2x - 8
= 8x - 5
Answer: 8x - 5
Checking back to 3(2x + 1):
= 8x - 5 - 2(x - 4)
= 8x - 5 - 2x + 8
= 6x + 3 or 3(2x + 1)
3(2x + 1) + 2(x - 4) Given
6x + 3 + 2x - 8 Distribute
8x - 5 Add/ Subtract Like numbers
Final answer 8x - 5
參考: honors math student
You would use the distubutive propery to simplify this problem. 4(x-3)^2 - 2(2 x+1)^2 + 7 = 3 (4x-12)^2 - (4x+2)^2 + 7=3 16x-144-16x+4+7=3
3(2x+1)+2(x-4)
6x+3+2x-8= 8x-5
3(2x + 1) + 2(x - 4)
= 3*2x + 3*1 + 2*x - 2*4
= 6x + 3 + 2x - 8
= 6x + 2x + 3 - 8
= 8x - 5
Expand it first.
6x+1+2x-4
Then simplify it.
8x-3 <======== answer
3(2x + 1) =6x+3
2 (x-4) =2x-8
----------------------------
3(2x + 1) + 2 (x-4)=6x+3+2x-8=(8x-5)
Using the Distributive Property, multiply the individual terms:
(3*2x + 3*1) + (2*x-2*4)
Add like terms (Commutative Property)
(3*2x + 2*x) + (3*1 + -2*4)
(6*x + 2*x) + (3 - 8)
8*x - 5
3(2x+1)+2(x-4)=6x+3+2x-8
=6x+2x+3-8
=8x-5
收錄日期: 2021-05-01 12:17:58
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090418002238AAUsYTv
檢視 Wayback Machine 備份