find the solution set for the following inequality x^2 + 4 > 4x
it's probably really simple...but I'm stuck :(
find the solution set for the following inequality x^2 + 4 > 4x?
2009-04-17 3:31 pm
回答 (7)
2009-04-17 3:37 pm
✔ 最佳答案
x^2-4x+4 = (x-2)^2 > 0So, x can be any number except 2.
2009-04-17 3:55 pm
x² + 4 > 4x
x² - 2x > - 4 + (- 2)²
x² - 2x > - 4 + 4
(x - 2)² > 0
x - 2 > 0
x > 2
Answer: x > 2
x² - 2x > - 4 + (- 2)²
x² - 2x > - 4 + 4
(x - 2)² > 0
x - 2 > 0
x > 2
Answer: x > 2
2009-04-17 3:42 pm
x^2-4x+4>0
(x-2)^2>0
For all values of x from - infinity to + infinity,the poynomial
is >0 exept x=2,then it is =0
-inf<2 positive
x=0,poyn=0
x>2 poly>0
(x-2)^2>0
For all values of x from - infinity to + infinity,the poynomial
is >0 exept x=2,then it is =0
-inf<2 positive
x=0,poyn=0
x>2 poly>0
2016-05-26 8:07 pm
1.(a). x < 7 (b). x < -23/5 2.(a). x=3 (b). y=20/11 (c). 5=b 3.(A). OMIT (b). 35 units 4. My Computer wont let me draw the curve but it would be 4.
2009-04-18 11:15 am
x^2 + 4 > 4x
x^2 - 4x + 4 > 0
x^2 - 2x - 2x + 4 > 0
(x^2 - 2x) - (2x - 4) > 0
x(x - 2) - 2(x - 2) > 0
(x - 2)(x - 2) > 0
x - 2 > 0
x > 2
∴ x > 2
x^2 - 4x + 4 > 0
x^2 - 2x - 2x + 4 > 0
(x^2 - 2x) - (2x - 4) > 0
x(x - 2) - 2(x - 2) > 0
(x - 2)(x - 2) > 0
x - 2 > 0
x > 2
∴ x > 2
2009-04-17 3:46 pm
x > 2
2009-04-17 3:35 pm
x^2 -4 x + 4>0
(x-2)(x-2) > 0
|x|>2
(x-2)(x-2) > 0
|x|>2
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