Help find the product: (3xy)(-2x^2y^3)(x + y)?

👨🏻‍🏫 學術台數學

[匿名]

2009-04-16 10:14 am

Ben trying to solve this problem for a couple of hours to no avail. The answer in the book is
-6x^4y^4 -6x^3y^5

I don't understand how they got the answer

更新1:

Step-by-step would be nice so I can understand what's going on

更新2:

Well, all I needed to solve the problem was when Walid J listed "= -6x^3y^4 (x + y)" It lead me to the answer I was seeking. Thank you, I will list you as best answer after the 4 hours are up.

回答 (6)

Engr. Ronald

2009-04-16 10:29 am

✔ 最佳答案

(3xy)(-2x^2y^3)(x + y)
=-6x^3y^4(x+y)
=-6x^4y^4-6x^3y^5 answer//

參考: http://www.mathway.com/answer.aspx?p=calg?p=(3xy)(-2xSMB072ySMB073)(xSMB15+SMB15y)?p=2?p=?p=?p=?p=?p=?p=?p=0?p=?p=

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[匿名]

2009-04-19 10:00 pm

(3xy)(-2x^2y^3)(x+y)

(-6x^3y^4)(x+y)

-6x^4y^4- 6x^3y^5

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An ESL Learner

2009-04-16 5:30 pm

(3xy)(-2x^2y^3)(x + y)
= (3)(-2)(x)(x^2)(y)(y^3)(x + y)
= (-6)(x^3)(y^4)(x + y)
= (-6x^3y^4)(x + y)
= (-6x^3y^4)(x) - (6x^3y^4)(y)
= -6x^4y^4 - 6x^3y^5

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[匿名]

2009-04-16 5:26 pm

(3xy)(-2x^2y^3)(x + y)

(3xy)(-2x^2y^3) .........................1

(3 * - 2)(x * x^2)(y * y^3) = (-6)(x^1+2)(y^1+3)
= -6 * x^3 * y^4

Now (-6 * x^3 * y^4)(x+y)= x*(-6 * x^3 * y^4)+ y*(-6 *x^3 * y^4)

=-6x * x^1+3 * y^4 - 6y * x^3 * y^1+4

= -6*x^4*y^4 -6*x^3*y^5

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[匿名]

2009-04-16 5:22 pm

(3xy)(-2x^2y^3)(x + y)
Start with the first two terms:
(3xy)(-2x^2y^3)
-6(xy)(x^2y^3)
-6(x^(1+2)*y^(1+3))
-6x^3y^4
Now the third term
-6x^3y^4(x+y)
-6x(3+1)y^4 - 6(x^3y^(4+1)
-6x^4y^4 -6x^3y^5

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[匿名]

2009-04-16 5:19 pm

= -6x^3y^4 (x + y)

by using distribution law :

= - 6x^3y^4 (x) + - 6x^3y^4(y)

= - 6 x^4 y^4 - 6 x^3 y^5

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