Simplify (4/(x+2)) - (7/(x+2)^2)
I have completely forgotten how to do it...If someone could please explain it???
Thanks
Simple algebra question?
2009-04-14 6:59 am
回答 (4)
2009-04-14 7:06 am
✔ 最佳答案
(4/(x+2)) - (7/(x+2)^2)=[4(x+2) -7] /(x+2)^2
=[4x +8 -7]/(x+2)^2
=(4x +1)/(x+2)^2
2009-04-14 3:06 pm
4(x + 2) - 7
-----------------
(x + 2)²
4x + 1
-------------
(x + 2)
-----------------
(x + 2)²
4x + 1
-------------
(x + 2)
2009-04-14 2:49 pm
4/(x + 2) - 7/[(x + 2)^2]
= [4(x + 2)]/[(x + 2)^2] - 7/[(x + 2)^2]
= (4x + 8 - 7)/[(x + 2)^2]
= (4x + 1)/[(x + 2)^2]
= [4(x + 2)]/[(x + 2)^2] - 7/[(x + 2)^2]
= (4x + 8 - 7)/[(x + 2)^2]
= (4x + 1)/[(x + 2)^2]
2009-04-14 2:15 pm
-3/ x^3+ 6x^2 + 16x
first of all you need to foil (x+2)^2 then you need multiply it by (x+2) then add like terms to combine them, to make the common denominator, after that you have (4-7)/ x^3 + 6x^2 + 16x
then just subtract the top.
i hope that's the correct way to do it.... i'm a little rusty to, but i tried my best.
first of all you need to foil (x+2)^2 then you need multiply it by (x+2) then add like terms to combine them, to make the common denominator, after that you have (4-7)/ x^3 + 6x^2 + 16x
then just subtract the top.
i hope that's the correct way to do it.... i'm a little rusty to, but i tried my best.
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