5條 maths 一定要詳細解答plz

回答 (1)

2009-04-13 8:02 am
✔ 最佳答案

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(b)
sin(180 o +θ)cos2(360 o -θ)+sin3(360 o -θ)
=(-sinθ)(cos2θ)-sin3θ
=(-sinθ)(1-sin2θ)-sin3θ
=-sinθ+ sin3θ- sin3θ
=-sinθ











14(a)
L.H.S.=tanA
=tan[180o-(B+C)]
=-tan(B+C)
=R.H.S.
(b)

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2009-04-13 00:04:10 補充:
17)
sinθcosθ=2/5


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