hkcee 1991
Qs 18
a) Given that tanx = ktany
i ) Show that sin(x+y)=(k+1)cosxsiny.
ii)Hence, show that (k+1)sin(x-y)=(k-1)sin(x+y).
b) Given that tan(Θ+10°)= ktan(Θ-20°)
has solution in Θ.
i) Show that sin(2Θ-10°)= (k+1)/2(k-1).
ii) Hence, find the range of possible values of k.
c) Find the general solution of
tan(Θ+10°)= -2tan(Θ-20°),
correct the answer to nearest 0.1 degree.