chemistry (volumetric analysis

2009-04-12 7:41 am
1. You are provided with 13.82g of potassium carbonate to prepare potassium carbonate solution.
(a) Calculate the no. of mole of potassium carbonate provided
(b) If it is dissolved in water to make a solution with 250 cm^3, calculate the concetntration of potassium carbonate in
(i) M (ii) g/ dm^3


(c) Calculate the volume of the resulting solution if a 0.25M potassium carbonate solution is to be prepared.

回答 (1)

2009-04-12 9:29 am
✔ 最佳答案
(a) Calculate the no. of mole of potassium carbonate provided
Firstly, u have to know the formula of potassium carbonate, which is K2(CO3), the mass of 1 mole of this compound would be (the Ar of K = 39.098, C = 12.011, O=15.999):
Ar = (39.098 x 2)+ (12.011+ 15.999 x 3) = 138.204g
The mass of potassium carbonate u have is 13.82. Therefore, the number of moles in ur sample would be
13.82/138.204 = 0.1 mole
bi) u have to apply this formula:
mole = conc x vol/1000
0.1 = conc x 250/1000
conc. = 0.4M

bii) The answer you got from the above is having an unit of mol/dm^3. as mentioned , 1 mole of substance has mass of 138.2g, 0.4 mole would have mass of 55.2816g. THis means that the concentration of the solution would be 55.2816g/dm^3
ci) the mole of sample u were given was 0.1mole, using the formula of
mole = conc x vol/1000
0.1 = 0.25 x vol/1000
vol = 400cm^3
when u answer this question, try to input the values into the calculator=]

參考: CE and A-LEVEL chem =]


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