g(x)=5x^3-2x^2+3x-7 given g(2)?
回答 (7)
2009-04-10 2:47 pm
✔ 最佳答案
g(x)=5x^3-2x^2+3x-7g(2)=5(2)^3-2(2)^2+3(2)-7
=5(8)-2(4)+6-7
=40-8+6-7
=31 answer//
2009-04-10 4:31 pm
g(x) = 5x^3 - 2x^2 + 3x - 7
g(2) = 5(2)^3 - 2(2)^2 + 3(2) - 7
g(2) = 5(8) - 2(4) + 6 - 7
g(2) = 40 - 8 + 6 - 7
g(2) = 31
g(2) = 5(2)^3 - 2(2)^2 + 3(2) - 7
g(2) = 5(8) - 2(4) + 6 - 7
g(2) = 40 - 8 + 6 - 7
g(2) = 31
2009-04-10 2:45 pm
g(x) = 5x^3 - 2x^2 + 3x - 7
g(2)
= 5(2)^3 - 2(2)^2 + 3(2) - 7
= 5(8) - 2(4) + 6 - 7
= 13 - 8 - 1
= 13 - 9
= 4
g(2)
= 5(2)^3 - 2(2)^2 + 3(2) - 7
= 5(8) - 2(4) + 6 - 7
= 13 - 8 - 1
= 13 - 9
= 4
2009-04-10 2:40 pm
G(2) = 5*2^3 - 2*2^2 + 3*2 - 7 =
5*8 - 2*4 + 6 - 7 =
40 - 8 - 1 = 31
5*8 - 2*4 + 6 - 7 =
40 - 8 - 1 = 31
2009-04-10 2:37 pm
31
2009-04-10 2:36 pm
Here g(x)=5x^3-2x^2+3x-7-----(i)
So putting x=2 in both sides of (i), we get
g(2)=5*(2)^3-2*(2)^2+3*2-7=40-8+6-7=31 [Answer]
So putting x=2 in both sides of (i), we get
g(2)=5*(2)^3-2*(2)^2+3*2-7=40-8+6-7=31 [Answer]
2009-04-10 2:33 pm
416
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