Factor the polynomial a2 - 4ac + ab - 4bc?
回答 (7)
2009-04-09 7:37 pm
✔ 最佳答案
a^2 - 4ac + ab - 4bcFactor out a from the first pair:
a(a - 4c) + ab - 4bc
Factor out b from the second pair:
a(a - 4c) + b(a - 4c)
Factor out a - 4c from these two terms:
(a - 4c)(a + b).
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If you like, you can check that this answer makes sense by multiplying it out:
(a - 4c)(a + b) = a^2 + ab - 4ac - 4bc = a^2 - 4ac + ab - 4bc.
2016-05-24 10:21 am
a^3 + b^2 + a^2b + ab = a^3 + a^2b + ab + b^2 = a^2(a + b) + b(a + b) = (a + b)(a^2 + b)
2009-04-09 7:41 pm
(a-4c)(a+b)
2009-04-09 7:39 pm
a^2 - 4ac + ab - 4bc
This is what we call "a quadratic in disguise".
Split it like this:
(a^2 - 4ac) + (ab - 4bc)
Now factor each part:
a(a - 4c) + b(a - 4c)
And now just take out the "parts"
(a+b)(a-4c)
Have a good day!
This is what we call "a quadratic in disguise".
Split it like this:
(a^2 - 4ac) + (ab - 4bc)
Now factor each part:
a(a - 4c) + b(a - 4c)
And now just take out the "parts"
(a+b)(a-4c)
Have a good day!
2009-04-09 7:37 pm
a^2 - 4ac + ab - 4bc
= a^2 + ab - 4ac - 4bc
= (a^2 + ab) - (4ac + 4bc)
= a(a + b) - 4c(a + b)
= (a + b)(a - 4c)
= a^2 + ab - 4ac - 4bc
= (a^2 + ab) - (4ac + 4bc)
= a(a + b) - 4c(a + b)
= (a + b)(a - 4c)
2009-04-09 7:37 pm
a2 - 4ac + ab - 4bc
(a-4c)(a+b)
(a-4c)(a+b)
2009-04-09 7:37 pm
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收錄日期: 2021-05-01 12:18:32
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