2x+3y=1 how do i get y by itself?
回答 (6)
2009-04-09 3:57 pm
✔ 最佳答案
OK2x+3y=1 ; first, subtract 2x from both sides
3y = 1-2x ; now write it like we are used to seeing
3y = -2x + 1 ; now divide both sides by 3
y = (-2x +1)/3 ; finally, place this into the slope intercept form
y = -2/3x + 1/3
Hope that helps.
2009-04-09 11:05 pm
2x + 3y = 1
3y = 1 - 2x
y = (1 - 2x)/3
y = 1/3 - 2/3x
Answer: y = 1/3 - 2/3x
Checking:
2x + 3(1/3 - 2/3x) = 1
2x + 1 - 2x = 1
1 = 1
3y = 1 - 2x
y = (1 - 2x)/3
y = 1/3 - 2/3x
Answer: y = 1/3 - 2/3x
Checking:
2x + 3(1/3 - 2/3x) = 1
2x + 1 - 2x = 1
1 = 1
2009-04-09 11:29 pm
First subtract 2x from both sides to get:
3y=1-2x
Now, divide both sides by 3:
y=(1/3)-(2/3)x which you can write as (-2/3)x+(1/3)
3y=1-2x
Now, divide both sides by 3:
y=(1/3)-(2/3)x which you can write as (-2/3)x+(1/3)
2009-04-09 11:03 pm
2x+3y=1
3y=1-2x
y=(1-2x)/3 answer//
3y=1-2x
y=(1-2x)/3 answer//
2009-04-09 11:02 pm
2x + 3y = 1
3y = -2x + 1
y = (-2x + 1)/3
3y = -2x + 1
y = (-2x + 1)/3
2009-04-09 10:55 pm
Subtract 2x from each side.
3y = 1 - 2x
Divide both sides by 3.
y = ( 1 - 2x )/3
y = 1/3 - 2/3x
3y = 1 - 2x
Divide both sides by 3.
y = ( 1 - 2x )/3
y = 1/3 - 2/3x
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