㏑N(t)=5.89-e^(1-0.18t)
(a)證明dN(t)/dt=0.18N(t)e^(1-0.18t)。
(b)求d^N(t)/dt^2。
唔識做
關於微分的高考試題。
2009-04-09 11:20 pm
回答 (2)
2009-04-10 10:00 pm
2009-04-09 11:26 pm
(a)
d/dt ( e^t ) = e^t
d/dt [e^f(t)] = e^t * d/dt f(t) {Chain rule}
(b)
d^N(t)/dt^2 should be d^2N(t)/dt^2
Use Product rule too.
d/dt ( e^t ) = e^t
d/dt [e^f(t)] = e^t * d/dt f(t) {Chain rule}
(b)
d^N(t)/dt^2 should be d^2N(t)/dt^2
Use Product rule too.
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https://hk.answers.yahoo.com/question/index?qid=20090409000051KK01063