Factor out the polynomial a^2-b^2+7a-7b?
回答 (11)
2009-04-09 2:38 pm
✔ 最佳答案
a^2 - b^2 + 7a - 7b= [a^2 - b^2] + [7a - 7b]
= [(a + b) (a - b)] + 7 [a - b]
= (a - b) [a + b + 7]
Thats it dear.
2009-04-09 12:50 pm
= a² - b² + 7a - 7b
= (a + b)(a - b) + 7(a - b)
= (a + b + 7)(a - b)
Answer: (a - b)(a + b + 7)
= (a + b)(a - b) + 7(a - b)
= (a + b + 7)(a - b)
Answer: (a - b)(a + b + 7)
2009-04-08 9:54 pm
a^2-b^2+7a-7b
(a +b)(a-b) + 7(a-b)
(a + b +7)(a-b)
(a +b)(a-b) + 7(a-b)
(a + b +7)(a-b)
2009-04-08 9:55 pm
a^2-b^2+7a-7b
= (a-b)(a+b)+7(a-b) grouping
= (a-b)[a+b+7] take out the common bracket(a-b)
= (a-b)(a+b)+7(a-b) grouping
= (a-b)[a+b+7] take out the common bracket(a-b)
2009-04-12 8:39 pm
(a-b)(a+b)+7(a-b)=
=(a-b)(a+b+7)
=(a-b)(a+b+7)
2009-04-09 8:30 am
a(a+7) - b(b+7)
2009-04-08 11:34 pm
a^2 - b^2 + 7a - 7b
= (a^2 - b^2) + (7a - 7b)
= (a + b)(a - b) + 7(a - b)
= (a - b)[(a - b) + 7)]
= (a - b)(a + b + 7)
= (a^2 - b^2) + (7a - 7b)
= (a + b)(a - b) + 7(a - b)
= (a - b)[(a - b) + 7)]
= (a - b)(a + b + 7)
2009-04-08 10:19 pm
a^2 - b^2 + 7a - 7b
= (a - b)(a + b) + 7(a - b)
= (a - b)(a + b + 7)
= (a - b)(a + b) + 7(a - b)
= (a - b)(a + b + 7)
2009-04-08 10:16 pm
a^2-b^2+7a-7b
(a-b)(a+b) + 7(a-b)
(a-b)(a+b+7)
That's it Maths rock
(a-b)(a+b) + 7(a-b)
(a-b)(a+b+7)
That's it Maths rock
2009-04-08 9:57 pm
First, there's the a^2 - b^2 = (a-b)(a+b)... next you use the distributive property on the 7a - 7b...
(a-b)(a+b) + 7(a-b)
There's a common factor between these two terms, so you can use the distributive property again...
(a-b)(a+b+7)
Make sense?
(a-b)(a+b) + 7(a-b)
There's a common factor between these two terms, so you can use the distributive property again...
(a-b)(a+b+7)
Make sense?
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