✔ 最佳答案
The answer is C.
Assume that the numbers of moles of MCO3 and NHCO3 are h mol and k mol respectively.
MCO3 + H2A → MA + H2O + CO2
No. of moles of MCO3 used = h mol
No. of moles of H2A used = h mol
No. of moles of CO2 formed = h mol
2NHCO3 + H2A → N2A + 2H2O + 2CO2
No. of moles of NHCO3 used = k mol
No. of moles of H2A used = k/2 mol
No. of moles of CO2 formed = k mol
Total no. of moles of H2A used :
h + (k/2) = 0.05 x (110/1000)
h + (k/2) = 0.0055
2h + k = 0.011
14h + 7k = 0.077 ...... (1)
Total no. of CO2 formed:
h + k = 168/24000
h + k = 0.007
11h + 11k = 0.077 ...... (2)
(1) = (2)
14h + 7k = 11h + 11k
3h = 4k
h : k = 4 : 3
=