If y = x^(sqrt 2), what is dy/dx ?
Differentiation
2009-04-07 6:47 pm
回答 (2)
2009-04-07 8:55 pm
✔ 最佳答案
y=x^(sqrt 2)dy/dx=(sqrt 2)x^[(sqrt 2)-1]
Since for f(x)=x^r , f'(x)=rx^(r-1) for any real number r.
2009-04-09 4:15 am
y=x^(sqrt 2)
since (sqrt 2) is a constant, according to the power rule,
dy/dx=(sqrt 2)*x^((sqrt 2)-1)
2009-04-08 20:16:02 補充：
i.e.
1.41421356x^0.41421356
since (sqrt 2) is a constant, according to the power rule,
dy/dx=(sqrt 2)*x^((sqrt 2)-1)
2009-04-08 20:16:02 補充：
i.e.
1.41421356x^0.41421356
收錄日期: 2021-04-22 00:40:47
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090407000051KK00398