F.4 maths 2題唔識做!!!!

2009-04-06 9:22 pm
1.factorize 3ab-3a+2b-2.
hence solve 3cosxsinx+2sinx=3cosx+2 for 0度≤x≤360度

2.solve the following equations for 0度≤x≤360度
a)cosx=cos(-20度)
b)3sinx+2 cos x=4sinx

回答 (3)

2009-04-06 10:02 pm
✔ 最佳答案
1
3ab-3a+2b-2
=3a(b-1)+2(b-1)
=(b-1)(3a+2)


3cosxsinx+2sinx=3cosx+2
3cosxsinx-3cosx+2sinx-2=0
(sinx-1)(3cosx+2)=0
sinx=1 或 cosx=-2/3
x=90,132,312

a)cosx=cos(-20)
cosx=cos20
x=20或 340
b)3sinx+2 cos x=4sinx
3tanx+2=4tanx
tanx=2
x=63.4 或243

2009-04-06 14:03:15 補充:
有個度符號~!
2009-04-06 11:29 pm
1.3ab-3a+2b-2
=(3a+2)(b-1)
(consider that cosx=a&sinx=b)
3cosxsinx+2sinx=3cosx+2
3cosxsinx-3cosx+2sinx-2=0
(3cosx+2)(sinx-1)=0
cosx=-2/3 or sinx=1
∴x=131.81度 or x=228.19度 or x=90度

2.a)cosx=cos(-20度)
cos(20度)=cos(340度)
∴x=20度 or x=340度

(b)3sinx+2cosx=4sinx
2cosx=sinx
sinx/cosx=2
tanx=2
∴x=63.435度 or x=243.435度
2009-04-06 10:03 pm
1.factorize 3ab-3a+2b-2.
hence solve 3cosxsinx+2sinx=3cosx+2 for 0度≤x≤360度
sol
3ab-3a+2b-2
=(3a+2)(b-1)
3cosxsinx+2sinx=3cosx+2
3cosxsinx-3cosx+2sinx-2=0
(3cosx+2)(sinx-1)=0
so cosx=-2/3 or sinx=1
so x=131.81度 or x=228.19度 or x=90度

2.solve the following equations for 0度≤x≤360度
a)cosx=cos(-20度)
b)3sinx+2 cos x=4sinx
sol
(a) cosx=cos(-20度)=cos(20度)=cos(340度)
x=20度 or x=340度
(b)3sinx+2cosx=4sinx
2cosx=sinx
tanx=sinx/cosx=2/1
x=63.435度 or x=243.435度



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