微積分(求極限)
1. lim Θ→0 (3sinΘ-sin2Θ)/2Θ
2.lim x→0 (sin3x-3sinx)/x^3
3.lim x→∞ ((4x-3)/5x+1)^3
a-maths (極限)
2009-04-05 12:52 am
回答 (2)
2009-04-05 1:06 am
✔ 最佳答案
Please have a look of the followings:圖片參考：http://i726.photobucket.com/albums/ww265/physicsworld2010/physicsworld03Apr041705.jpg?t=1238836000
圖片參考：http://i726.photobucket.com/albums/ww265/physicsworld2010/physicsworld04Apr041705.jpg?t=1238836005
參考: Physics king
2009-04-05 1:09 am
1. lim Θ→0 (3sinΘ-sin2Θ)/2Θ = 3/2
2. lim x→0 (sin3x-3sinx)/x^3 = -4
3. lim x→∞ ((4x-3)/5x+1)^3 = 64/125
2009-04-04 17:10:53 補充：
Correction:
lim Θ→0 (3sinΘ-sin2Θ)/2Θ = 1/2
2. lim x→0 (sin3x-3sinx)/x^3 = -4
3. lim x→∞ ((4x-3)/5x+1)^3 = 64/125
2009-04-04 17:10:53 補充：
Correction:
lim Θ→0 (3sinΘ-sin2Θ)/2Θ = 1/2
收錄日期: 2021-04-19 14:04:55
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https://hk.answers.yahoo.com/question/index?qid=20090404000051KK01106