can anyone solve for y in this equation?
回答 (6)
2009-04-02 3:15 pm
✔ 最佳答案
85 = Y - 145 + 0.5 (Y + 40 + 0.25Y)85 = Y - 145 + 0.5Y + 20 + 0.125Y
85 + 145 - 20 = Y + 0.5Y + 0.125Y
210 = Y (1 + 0.5 + 0.125)
210 = Y (1.625)
210 / 1.625 = Y
Y = 129.23
2009-04-02 3:08 pm
85=Y-145+0.5(Y+40+0.25Y)
y - 145 + 0.5y + 20 + 0.125y = 85
1.625y - 125 = 85
1.625y = 210
y = 129.230769
y - 145 + 0.5y + 20 + 0.125y = 85
1.625y - 125 = 85
1.625y = 210
y = 129.230769
2009-04-02 3:20 pm
85=Y-145+.5(Y+40+.25Y)
85=Y+(-)145+.5Y+20+.125Y
85=1.625Y+(-)145+20
85=1.625Y+(-)125
-40=1.625Y
-24.615384615=Y
Y=-24.615384615
You can simplify the answer if you want
85=Y+(-)145+.5Y+20+.125Y
85=1.625Y+(-)145+20
85=1.625Y+(-)125
-40=1.625Y
-24.615384615=Y
Y=-24.615384615
You can simplify the answer if you want
參考: My Mind
2009-04-02 3:18 pm
85=Y-145+0.5(Y+40+0.25Y)
85=Y-145+0.5Y+20+0.125Y
85=1.625Y-125
85+125=1.625Y
210=1.625Y
Y=129.2307692 answer//
85=Y-145+0.5Y+20+0.125Y
85=1.625Y-125
85+125=1.625Y
210=1.625Y
Y=129.2307692 answer//
參考: check my answer here:
http://www.mathway.com/answer.aspx?p=trig?p=85SMB01Y-145+0.5(Y+40+0.25Y)?p=1?p=?p=?p=?p=?p=?p=?p=0?p=?p=
2009-04-02 3:17 pm
85=Y-145+0.5(Y+40+0.25Y)
85=Y-145+0.5(1.25Y+40)
85=Y-145+0.625Y+20
85=1.625Y-125
Y=(85+125)/1.625
Y=210/1.625
Y=1680/13
Y=129.23
85=Y-145+0.5(1.25Y+40)
85=Y-145+0.625Y+20
85=1.625Y-125
Y=(85+125)/1.625
Y=210/1.625
Y=1680/13
Y=129.23
2009-04-02 3:12 pm
85 = y - 145 + 0.5(y + 40 + 0.25y)
85 = y - 145 + 0.5y + 20 + 0.125y
85 = (1.625)y - 125
1.625y = 85 + 125 = 210
y = 210/1.625
y = 129.23
85 = y - 145 + 0.5y + 20 + 0.125y
85 = (1.625)y - 125
1.625y = 85 + 125 = 210
y = 210/1.625
y = 129.23
收錄日期: 2021-05-01 12:14:56
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