7x-(x-4)(-x-3) Can someone help me out with this?
Do I apply the 7x- to the first bracket or just the - or do I treat it as a whole other bracket set?
Thanks for your help!
7x-(x-4)(-x-3) ... :|?
2009-04-01 3:15 pm
回答 (12)
2009-04-01 3:27 pm
✔ 最佳答案
7x - (x - 4)(-x - 3)= 7x - [(x(-x) + x(-3) + (-4)(-x) + (-4)(-3)]
= 7x - (-x^2 - 3x + 4x + 12)
= 7x - (-x^2 + x + 12)
= 7x + x^2 - x - 12
= x^2 + 6x - 12
2017-01-18 9:51 pm
5/x + 6/x = 12 multiply the completed equation with the help of x 5+6 = 12x 11 = 12x divide entire equation with the help of 12 11/12 = x do an comparable for the 2d equation 4/x = 2/3 4 = 2/3 x 4/ (2/3) = x dividing with the help of a fraction is the comparable as multiplying with the help of the reciprocal 4 * (3/2) = x 4 * a million.5 = x 6 = x
2009-04-04 9:06 pm
7x - ( - x² - 3x + 4x + 12)
7x - (- x² + x + 12)
7x + x² - x - 12
x² + 6x - 12
7x - (- x² + x + 12)
7x + x² - x - 12
x² + 6x - 12
2009-04-01 3:59 pm
7x - (x - 4)(-x - 3)
= 7x - (-x*x + 4*x - x*3 + 4*3)
= 7x - (-x^2 + 4x - 3x + 12)
= 7x - (-x^2 + x + 12)
= 7x + x^2 - x - 12
= x^2 + 6x - 12
= 7x - (-x*x + 4*x - x*3 + 4*3)
= 7x - (-x^2 + 4x - 3x + 12)
= 7x - (-x^2 + x + 12)
= 7x + x^2 - x - 12
= x^2 + 6x - 12
2009-04-01 3:33 pm
7x-(x-4)(-x-3)
=7x-(-x^2+x+12)
=7x+x^2-x-12
=x^2+6x-12 answer//
=7x-(-x^2+x+12)
=7x+x^2-x-12
=x^2+6x-12 answer//
參考: check my answer here:
http://www.mathway.com/answer.aspx?p=trig?p=7x-(x-4)(-x-3)?p=2?p=?p=?p=?p=?p=?p=?p=0?p=?p=
2009-04-01 3:32 pm
7x – (x – 4)(–x – 3)
= 7x – (–x² + x + 12)
= 7x + x² – x – 12
= x² + 6x – 12
Done
= 7x – (–x² + x + 12)
= 7x + x² – x – 12
= x² + 6x – 12
Done
2009-04-01 3:22 pm
7x - (x - 4)(-x - 3)
= 7x - [(x(-x) + x(-3) + (-4)(-x) + (-4)(-3)]
= 7x - (-x^2 - 3x + 4x + 12)
= 7x - (-x^2 + x + 12)
= 7x + x^2 - x - 12
= x^2 + 6x - 12
= 7x - [(x(-x) + x(-3) + (-4)(-x) + (-4)(-3)]
= 7x - (-x^2 - 3x + 4x + 12)
= 7x - (-x^2 + x + 12)
= 7x + x^2 - x - 12
= x^2 + 6x - 12
2009-04-01 3:21 pm
7x-(x-4)(-x-3) = 7x + (-1)*(x-4)*(-x-3)
7x + (-x+4)*(x+3) = 7x + -x^2+x+12 = -x^2+8x+12
7x + (-x+4)*(x+3) = 7x + -x^2+x+12 = -x^2+8x+12
2009-04-01 3:21 pm
7x - (x-4)(-1)(x+3)
= 7x + (x-4)(x+3)
= 7x + x^2 + 3x - 4x - 12
= x^2 + 6x - 12
= 7x + (x-4)(x+3)
= 7x + x^2 + 3x - 4x - 12
= x^2 + 6x - 12
2009-04-01 3:21 pm
7x-(x-4)(-x-3) =
7x - (-x^2 -3x +4x +12) =
7x +x^2 +3x -4x -12 =
x^2 +6x -12
Careful: Tiffany's answer is wrong
7x - (-x^2 -3x +4x +12) =
7x +x^2 +3x -4x -12 =
x^2 +6x -12
Careful: Tiffany's answer is wrong
收錄日期: 2021-05-01 12:15:37
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