Factor: 2x squared - 3x - 2?
回答 (10)
2009-04-01 10:42 am
✔ 最佳答案
2x^2-3x-2=(2x+1)(x-2) answer//
參考: check my answer here:
http://www.mathway.com/answer.aspx?p=calg?p=2xSMB072-3x-2?p=213?p=?p=?p=?p=?p=?p=?p=0?p=?p=
2009-04-01 5:41 pm
2x² - 3x - 2
= (2x + 1)(x - 2)
Done
= (2x + 1)(x - 2)
Done
2009-04-01 5:38 pm
(2x+1)*(x-2)
2009-04-01 5:38 pm
2x² – 3x – 2 = (x – 2)(2x + 1)
2009-04-01 5:36 pm
2x^2 - 3x - 2
2x^2 - 4x + x - 2
2x(x-2) + (x-2)
(2x + 1)(x - 2)
2x^2 - 4x + x - 2
2x(x-2) + (x-2)
(2x + 1)(x - 2)
2009-04-01 5:36 pm
=(2x+1)(x-2)
using the FOIL method you should end up with 2x^2-3x-2 again.
using the FOIL method you should end up with 2x^2-3x-2 again.
2009-04-01 5:35 pm
2x^2 - 3x - 2 = (2x+1)(x - 2)
2009-04-01 5:35 pm
2x^2 - 3x - 2
= 2x^2 + x - 4x - 2
= (2x^2 + x) - (4x + 2)
= x(2x + 1) - 2(2x + 1)
= (2x + 1)(x - 2)
= 2x^2 + x - 4x - 2
= (2x^2 + x) - (4x + 2)
= x(2x + 1) - 2(2x + 1)
= (2x + 1)(x - 2)
2009-04-01 5:38 pm
It is a quadratic, so assuming you've learned this:
Let 2x^2 - 3x - 2 = 0
2x^2 - 3x - 2 = 0
Split up -3x into -4x + 1x
2x^2 - 4x + 1x - 2 = 0
Take out a common factor of 2x for the first pair and 1 for the second pair
2x (x-2) + 1(x-2) = 0
Take out a common factor of (x-2)
(x-2) (2x+1) = 0
therefore,
x-2 = 0
x = 2
and
2x+1 = 0
2x = -1
x = -1/2
solutions are x=2 and x=-1/2
Let 2x^2 - 3x - 2 = 0
2x^2 - 3x - 2 = 0
Split up -3x into -4x + 1x
2x^2 - 4x + 1x - 2 = 0
Take out a common factor of 2x for the first pair and 1 for the second pair
2x (x-2) + 1(x-2) = 0
Take out a common factor of (x-2)
(x-2) (2x+1) = 0
therefore,
x-2 = 0
x = 2
and
2x+1 = 0
2x = -1
x = -1/2
solutions are x=2 and x=-1/2
2009-04-01 5:35 pm
(x-2)(2x-1)
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