Please solve: 2 + x (less than or equal to) 6?

2009-04-01 7:41 am

回答 (8)

2009-04-01 7:44 am
✔ 最佳答案
subtract 2 from both sides:

x <= 4
2009-04-01 7:47 am
2 + x <= 6
x <= 6 - 2
x <= 4

Answer: x <= 4
2016-12-18 11:32 pm
x^2 + 7x + 6 <= 6 x^2 + 7x <= 0 || Subtract 6 from the two factors x(x+7) <= 0 So there you circulate. build your indicators table, and calculate that. x^2 + 7x + 6 could be factored (x + 6)(x + a million), yet you do no longer choose for the zeroes of that - you elect for to get the <= 6 area. consequently, you could subtract 6 from the two factors. that's the step you're lacking.
2009-04-01 7:50 am
2+1mulitiple2=6
2009-04-01 7:47 am
2+x <= 6
2-2+x <= 6-2
x <= 4
2009-04-01 7:46 am
2+x<6
x<6-2
x (is less than or equal to)4
2009-04-01 7:46 am
2+x<=6
x=<4
2009-04-01 7:45 am
2 + x =< 6
x =< 4


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